Two shooters shoot at the target. The probability of being on target for one shooter

Two shooters shoot at the target. The probability of being on target for one shooter is 0.8 for the other 0.9. Find the probability that the target will not be hit by any bullets

Since the total probability is always 1, the probability of not hitting the target by the 1st shooter is:

1 – 0.8 = 0.2.

And the 2nd:

1 – 0.9 = 0.1.

Since the events are independent (the arrows are different), the probability of a common event is:

0.2 * 0.1 = 0.02.

Answer: The probability of not hitting any of the bullets is 0.02.