Two spirals of an electric stove with a resistance of 10 ohms each are connected in series and connected to a network with a voltage of 220 V. Water weighing 1 kg boiled on this stove after 174 s. What is the efficiency of the process if the initial water temperature is 20 ° C?
Efficiency = Ap / Az * 100%
Ap = s * m * T = 80c = Q
Az = U ^ 2 * t / Ro = 220 * 220 * 174/20
Efficiency = (80 * 4200 * 20 / (220 * 220 * 174)) * 100% = 79%
Answer: The efficiency is approximately 79%
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