Two tourists go simultaneously to the city located at a distance of 30 km from them. the first tourist walks 1 km

Two tourists go simultaneously to the city located at a distance of 30 km from them. the first tourist walks 1 km more per hour than the second. so he comes to town 1 hour earlier. find the speed of the second tourist

1. We take for x (km / h) the speed with which the second tourist is walking; the first tourist passes in hour is 1 kilometer more, so its speed is (x + 1) km / h.

2. The travel time of the first tourist is 30 / (x + 1) hours, the travel time of the second tourist is 30 / x hours.

3. Considering that the first tourist arrives at the destination 1 hour earlier than the second, we will compose

the equation:

30 / x- 30 / (x + 1) = 1;

(30x + 30 – 30x) / x (x + 1) = 1;

x² + x – 30 = 0;

The first value x = (- 1 + √1 + 30 x 4) 2 = (- 1 + (1 + 120) / 2 = (- 1 + 11) / 2 = 5 km / h.

The second value is x = (- 1 – 11) / 2 = – 6. Not accepted.

Answer: the speed of the second tourist is 5 km / h.