Two trains left at different times towards each other from two stations, the distance between which is 588 km

Two trains left at different times towards each other from two stations, the distance between which is 588 km. The first train passed 48 km in an hour and passed 336 km before the meeting. The second train traveled 15 km more per hour than the first. How many hours did one of the trains leave before the other?

Let’s find how many hours 1 train was on the way.

Distance. which the train passed by we divide by its speed.

336: 48 = 7 (h) – 1 train was on the way.

Let’s find the speed of the second train.

Increase the speed of 1 train by 15.

48 + 15 = 63 (km / h) – speed of 2 trains.

Let’s find how long the 2nd train passed before the meeting.

588 – 336 = 252 (km) – 2 train passed before the meeting.

Let’s find how many hours train 2 was on the way.

252: 63 = 4 (h) – there was 2 train on the way.

Let’s find how many one train left earlier.

7 – 4 = 3 (h)

Answer: 3 hours earlier.