Two trains left at the same time towards each other. The first train moved at a speed of 72 km / h
| March 17, 2021 | education
Two trains left at the same time towards each other. The first train moved at a speed of 72 km / h, and the second at 68 km / h. The second train covered 408 km before the meeting. How far was the first train to the meeting?
The solution of the problem:
1. Find out how long the second train was on the way before meeting the first train.
408/68 = 6 hours.
2. It is known that the trains were moving at the same time, so the first one was on the way for 6 hours too. Let’s calculate the path he traveled before meeting the second train.
6 * 72 = 432 kilometers.
Answer: The first train traveled 432 kilometers before meeting the second train.
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