Two trains simultaneously left to meet each other from two cities, the distance between which is 495 km
Two trains simultaneously left to meet each other from two cities, the distance between which is 495 km after 3 hours they met what is the speed of each train if it is known that the speed of one of them is 5 km per hour more than the speed of the other.
The solution of the problem.
We will solve this problem using the equation.
1. Let’s denote by x the speed of the first train.
2. Find the speed of the second train.
(x – 5) km / h.
3. Determine the distance that the first train will travel before the meeting.
x km / h * 3 h = 3 km.
4. Determine the distance that the second train will travel before the meeting.
(x – 5) km / h * 3 h = 3 * (x – 5) km.
5. Let’s compose and solve the equation.
3x + 3 * (x – 5) = 495;
6x – 15 = 495;
6x = 510;
x = 85.
6. The speed of the first train is x = 85 km / h.
7. Find the speed of the second train.
85 km / h – 5 km / h = 80 km / h.
Answer. The speed of one train is 85 km / h, and the second is 80 km / h.