Two trolleys move towards each other with the same speed of 5 m / s. Carts weights 1 kg and 4 kg.

| December 11, 2020 | education

Two trolleys move towards each other with the same speed of 5 m / s. Carts weights 1 kg and 4 kg. What will their speed be after the hitch is deployed?

To solve the problem, we use the momentum conservation law.
Impulse – p, p = mv, where v is the speed.
The OX axis is directed to the right.
On the left side there are impulses “to”: two impulses from two carts, plus they move towards each other, which means different signs in the projection.
On the right side there are impulses “after”: the carts move as a whole, the sum of the masses with a certain speed.
m1v1 – m2v2 = (m1 + m2) v
1kg * 5m / s – 4kg * 5m / s = (1kg + 4kg) * v
5-20 = 5v
-15 = 5v
v = – 3m / s
Minus, since the speed is directed against the direction of the OX axis.
Answer: v = 3 m / s.



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