Two weights weighing 0.24 and 0.26 kg are attached to the ends of the thread thrown over the fixed block. Determine the acceleration of the weights, the tension force of the thread and the distance between the weights 2 s after the start of the movement, if at the initial moment of time they were at the same height relative to the ground. Assume that the masses of the thread and the block are zero and the thread is inextensible.
2.6 -2.4 = 0.5a
0.2 = 0.5a
a = 0.4 m / s ^ 2
T = m1g + m1a = 2.496 H
s = at ^ 2/2 = 0.4 * 4: 2 = 0.8 m
Answer: 0.8 m; 0.4 m / s ^ 2; 2.496 N
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