Two weights weighing 2 kg and 4 kg, lying on a smooth horizontal surface, are connected by an inextensible

Two weights weighing 2 kg and 4 kg, lying on a smooth horizontal surface, are connected by an inextensible and weightless thread. The first load begins to pull with an evenly increasing force. When the force reaches 12 N, the thread breaks. What is the value of the tension force at this moment?

Given:
M1 = 2 kg
m2 = 4kg
F = 12H
Fн -?
Decision :
m2a = T
m1a + m2a = T
a = F / m1 + m2 from this it follows that
T = m2F / m1 + m2 = 4 * 12/2 + 4 = 8h
Answer: 8h