Two workers are sawing logs with a two-handed saw. Each of them pulls pollen 60 times a minute at a distance

Two workers are sawing logs with a two-handed saw. Each of them pulls pollen 60 times a minute at a distance of 60 cm and back with a force of 30 N. What work does one sawfly do in 5 minutes?

Initial data: n (the number of working movements when cutting a log in one minute) = 60 times; S1 (distance traveled in one cut) = 60 cm (0.6 m); F (labor force applied) = 30 N; t (duration of the sawfly operation) = 5 min.

The work that one sawfly will perform in a given time is determined by the formula: A = F * S = F * (S1 * n * t).

Calculation: A = 30 * (0.6 * 60 * 5) = 5400 J (5.4 kJ).

Answer: In 5 minutes one sawfly performs 5.4 kJ of work.