Under a force of 320 N, the shock absorber spring was compressed by 9mm.
| September 7, 2021 | education
Under a force of 320 N, the shock absorber spring was compressed by 9mm. How many millimeters the spring will be compressed under a load of 1.60 kN.
Task data: F1 (first force compressing the shock absorber spring) = 320 N; Δх1 (first compression) = 9 mm; F2 (load under consideration) = 1.6 kN (1600 N).
The compression of the taken shock absorber spring under a load of 1.6 kN is expressed from the equality: F1 / Δх1 = k (stiffness of the shock absorber spring) = F2 / Δх2, whence Δх2 = F2 * Δх1 / F1.
Let’s make a calculation: Δx2 = 1600 * 9/320 = 45 mm.
Answer: Under a load of 1.6 kN, the taken shock absorber spring will be compressed by 45 mm.
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