Under normal conditions, a certain mass of gas occupies a volume of 6m ^ 3. What volume will this gas occupy

Under normal conditions, a certain mass of gas occupies a volume of 6m ^ 3. What volume will this gas occupy during isothermal compression to a pressure 30 times higher than normal?

P1 = Pn.
P2 = 30 * Pн.
V1 = 6 m ^ 3.
T = const
V2 -?
According to Boyle-Mariotte’s law, at T = const, the equality is true: P1 * V1 = P2 * V2.
V2 = P1 * V1 / P2 = Pn * V1 / 30 * Pn = V1 / 30.
V2 = 6 m ^ 3/30 = 0.2 m ^ 3.
Answer: the gas will occupy a volume of V2 = 0.2 m ^ 3.