Under normal conditions, about 2.3 liters of hydrogen sulfide dissolves in 1 liter of water.
Under normal conditions, about 2.3 liters of hydrogen sulfide dissolves in 1 liter of water. Determine the mass fraction of hydrogen sulfide in the resulting solution.
To find out the mass fraction of hydrogen sulfide (hydrogen sulfide, H2S) in the resulting solution, we apply the formula: ωH2S = mH2S / mр-pa = VH2S * ρH2S / (VH2S * ρH2S + VH2O * ρH2O), where VH2S is the volume of hydrogen sulfide (VH2S = 2 , 3 l); ρH2S – density of hydrogen sulfide (const; ρH2S = 1.5206 g / l); VH2O – volume of water (VH2O = 1 l); ρH2O is the density of water (const; ρH2O = 1000 g / l).
Let’s calculate: ωH2S = VH2S * ρH2S / (VH2S * ρH2S + VH2O * ρH2O) = 2.3 * 1.5206 / (2.3 * 1.5206 + 1 * 1000) = 0.003485 or 0.3485%.
Answer: In the resulting solution, the mass fraction of hydrogen sulfide is 0.3485%.