Under normal conditions, what volume of hydrogen will be released when 4.8 magnesium is dissolved
Under normal conditions, what volume of hydrogen will be released when 4.8 magnesium is dissolved in an excess of hydrochloric acid?
The active element metallic magnesium, when it gets into hydrochloric acid, dissolves in it. The chemical process is described by the following equation:
Mg + 2HCl = MgCl2 + H2 ↑;
Let’s determine the chemical amount of the elementary magnesium substance that has entered into interaction.
For this purpose, we divide its mass by the weight of 1 mole of metallic magnesium (its molar weight).
M Mg = 24.0 grams / mol;
N Mg = 4.8 / 24 = 0.20 mol;
An equivalent amount of hydrogen gas will be synthesized.
Let’s find the volume of synthesized hydrogen.
To do this, multiply the amount of hydrogen gas substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters). The product will be equal to the volume of gas.
V H2 = 0.2 x 22.4 = 4.48 liters;