Under the action of a force of 2 kN, the car moves in such a way that its path is expressed

Under the action of a force of 2 kN, the car moves in such a way that its path is expressed by the dependence S = t – 0.1t2 (m). Determine the weight of the vehicle.

Given: F (force under which the car moves) = 2 kN (2 * 10 ^ 3 N); dependence of the car’s distance traveled on time S = t – 0.1t^2.

1) We calculate the constant acceleration of the car (it is necessary to determine the second-order derivative): a = S (t) ” = V (t) ‘= (t – 0.1t ^ 2)’ ‘= (1 – 0.1 * 2t) ‘= -0.1 * 2 = -0.2 m / s2 (slow motion).

2) Determine the mass of the car (Newton’s second law): m = F / a = 2 * 10 ^ 3 / 0.2 = 10 * 10 ^ 3 kg (10 tons).

Answer: The required vehicle mass is 10 tons.