Under the action of a force of 20 N, the spring lengthened by 0.1 m. The stiffness of the springs is?
| February 6, 2021 | education
To solve the presented problem, it is necessary to use the formula that relates the values of the elastic force: stiffness and elongation.
Let’s write the formula for the elastic force of the body:
Fcont = kx
or
Fcont = kΔl.
Hence the stiffness of the spring is:
k = Fcont / x = 20 N / 0.1 m = 200 N / m.
Answer: 200 N / m.
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