Under the action of a force of 3.2N, the spring lengthened by 5 cm by how much the spring would lengthen under the force of 4N.
| November 29, 2020 | education
First, let’s find the stiffness of the spring:
F = kx
5cm = 0.05m
k = F: x = 3.2: 0.05 = 64 N / m ^ 2
And now the spring extension:
F = kx
x = F: k = 4: 64 = 0.0625 (m)
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