Under the action of a force of 320 N, the shock absorber spring was compressed by 18 mm.
| February 8, 2021 | education
Under the action of a force of 320 N, the shock absorber spring was compressed by 18 mm. How much will the spring be compressed at a load of 3.20 kN.
Initial data: F1 (the first deforming force of the shock absorber spring) = 320 N; Δx1 (first spring deformation) = 18 mm (0.018 m); F2 (second deforming force) = 3.2 kN (3200 N).
The compression of the shock absorber spring is determined from the equality: F1 / Δx1 = k (stiffness of the shock absorber spring) = F2 / Δx2, whence Δx2 = F2 * Δx1 / F1.
Calculation: Δx2 = 3200 * 0.018 / 320 = 0.18 m.
Answer: With a load of 3.2 kN, the shock absorber spring will be compressed by 0.18 m.
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