Under the action of a force of 5 N, the spring lengthened by 8 cm by how much the spring will

Under the action of a force of 5 N, the spring lengthened by 8 cm by how much the spring will stretch if a body weighing 100 g is hung on it.

Find how much the spring stretches when one unit of force is applied

K = 8/5 = 1.6 cm / N.

Weight of cargo

m = 100 g = 100/1000 = 0.1 kg.

The body is suspended vertically, which means strength

F = m * g = 0.1 * 10 = 1 N.

Determine the tension of the spring at 100 g of load

S = K * F = 1.6 cm / H * 1 H = 1.6 cm.

Answer: 1.6 cm.