Under the action of a force of 50 N, a trolley weighing 40 kg moves with

Under the action of a force of 50 N, a trolley weighing 40 kg moves with an acceleration of about, 1 m / s ^ 2. find the force of resistance.

F = 50 N.

m = 40 kg.

a = 0.1 m / s2.

Fsopr -?

According to Newton’s 2 law, the resultant of all forces Fр is equal to the product of the body’s mass m by its acceleration a: Fр = m * a.

Fr = 40 kg * 0.1 m / s2 = 4 N.

The resultant of all forces Fр is called the vector sum of all forces that act on the body: Fр = F + Fсopr.

The resistance force Fcopr is always directed in the opposite direction of movement, therefore, for projections: Fр = F – Fcopr.

Fcopr = F – Fr.

Fcopr = 50 N – 4 N = 46 N.

Answer: the body is affected by a resistance force Fcopr = 46 N.