Under the action of a force of 50N, a trolley weighing 40 kg changes its speed by 1 m / s in 10 s. Find the force of resistance.

Given:

F = 50 Newton – the force acting on the trolley;

m = 40 kilograms – trolley weight;

dv = 1 m / s – change in speed over a period of time t;

t = 10 seconds – time span.

It is required to determine the resistance force Fcopr. (Newton).

Let’s find the acceleration with which the body moves:

a = dv / t = 1/10 = 0.1 m / s ^ 2.

Then, according to Newton’s second law:

F – Fcopr = m * a;

Fcopr = F – m * a = 50 – 40 * 0.1 = 50 – 4 = 46 Newtons.

Answer: the resistance force acting on the trolley is 46 Newtons.