Under the action of a weight of 0.2 kg, the spring was stretched by 4 cm. Determine the spring stiffness.
| May 5, 2021 | education
Given:
m = 0.2 kg is the weight of the cargo;
l = 4 centimeters = 0.04 meters – spring tension;
g = 10 m / s ^ 2 – acceleration of gravity.
It is required to determine the stiffness of the spring k (N / m).
The force acting on the spring is:
F = m * g = 0.2 * 10 = 2 N.
Hardness is equal to:
k = F / l = 2 / 0.04 = 50 N / m.
Answer: the spring rate is 50 N / m.
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