Under the action of an excess of magnesium, 224 ml of hydrogen were released from 1.48 g

| March 23, 2021 | education

Under the action of an excess of magnesium, 224 ml of hydrogen were released from 1.48 g of carboxylic acid. Determine the acid formula.

Let’s write down the reaction scheme and arrange the coefficients
Mg + 2XCOOH = H2 + (XCOO) 2Mg
Let us determine the amount of hydrogen substance n (H2) = V (H2) / Vm, where Vm = 22.4 l / mol is the molar volume
n (H2) = 0.224 / 22.4 = 0.01 mol
Let us determine the molar mass of the acid M (to-you), taking into account the fact that the amount of acid substance n (to-you) = 2 * n (H2) = 0.02 mol.
M (to-you) = m (to-you) / n (to-you), where m (to-you) is the mass of acid
M (to-you) = 1.48 / 0.02 = 74 g / mol
we find out the molar mass of the residue X, M (X) = M (to-you) – M (COOH), where M (COOH) = 45 g / mol is the molar mass of COOH
M (X) = 74 – 45 = 29 g / mol – this molar mass corresponds to CH3CH2
Acid formula CH3CH2COOH – propionic



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