Under the action of an excess of water on 512 g of calcium carbide, acytene with a volume of 134.4

Under the action of an excess of water on 512 g of calcium carbide, acytene with a volume of 134.4 l was formed. Find the yield fraction of the reaction product.

Acetylene is released when calcium carbide interacts with water.

CaC2 + 2H2O = Ca (OH) 2 + C2H2 ↑;

Let’s calculate the chemical amount of calcium carbide.

To do this, we sum up the molar weights of the elements that make up its molecule.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

N CaC2 = 512/64 = 8 mol;

Theoretically, the same molar amount of acetylene will be obtained.

Let’s calculate its volume. To this end, we multiply the amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).

V C2H2 = 8 x 22.4 = 179.2 liters;

The reaction yield is 134.4 / 179.2 = 0.75 = 75%;