Under the action of an excess of water on 512 grams of calcium carbide, acetylene with a volume of 134.4 liters
Under the action of an excess of water on 512 grams of calcium carbide, acetylene with a volume of 134.4 liters was formed. find the fraction of the yield of the reaction product.
Acetylene is synthesized by the interaction of calcium carbide with water.
CaC2 + 2H2O = Ca (OH) 2 + C2H2 ↑;
Let’s calculate the molar amount of calcium carbide.
To do this, let’s summarize the molar weights of the elements that make up this molecule.
M CaC2 = 40 + 12 x 2 = 64 grams / mol;
N CaC2 = 512/64 = 8 mol;
Theoretically, the same molar amount of acetylene will be obtained.
Let’s calculate its volume. For this purpose, we multiply the molar amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).
V C2H2 = 8 x 22.4 = 179.2 liters;
The reaction yield will be:
K = 134.4 / 179.2 = 0.75 = 75%;