Under the action of force 312, the spring with a length of 70.3 was lengthened by 60 cm.

Under the action of force 312, the spring with a length of 70.3 was lengthened by 60 cm. Find the numerical value of the cruelty of the spring.

Initial data: F (value of the force that deforms the spring) = 312 N; Δl (deformation (elongation) of this spring) = 60 cm.

SI system: Δl = 60 cm = 60/100 m = 0.6 m.

The numerical value (coefficient) of the spring stiffness is found from Hooke’s law:

F = F = k * Δl, whence k = F / Δl.

Let’s do the calculation:

k = 312 / 0.6 = 520 N / m.

Answer: The coefficient of stiffness of this spring is 520 N / m.