Under the action of mutually perpendicular forces, the moduli of which are F1 = 6H and F2 = 8H, the body from the state

Under the action of mutually perpendicular forces, the moduli of which are F1 = 6H and F2 = 8H, the body from the state of calmness for the time interval t = 4c has passed the path S = 16m in the direction of the resultant of these forces. Determine body weight.

Let us find the resultant of the two forces acting on the body. Since the directions of their actions are perpendicular, we will use the Pythagorean theorem:

F = √ (F1² + F2²) = √ (6² + 8²) = 10 N.

In accordance with Newton’s second law, the acceleration of a body is directly proportional to the force acting on it and inversely proportional to the mass of the body:

a = F / m.

The path traversed by the body during uniformly accelerated motion from the state of rest is described by the formula:

s = a * t² / 2.

Substitute the expression for determining the acceleration and express the desired body mass:

s = F / m * t² / 2;

m = F * t² / (2 * s);

m = 10 * 4² / (2 * 16) = 5 kg.