Under the action of sodium hydroxide on 500 grams of ammonium chloride, 178 liters

Under the action of sodium hydroxide on 500 grams of ammonium chloride, 178 liters of ammonia were obtained. Determine the volumetric ammonia yield.

Determine the chemical amount of ammonium chloride. To do this, we divide its weight by its molar mass.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

The amount of ammonium chloride will be:

N NH4 Cl = 500 / 53.5 = 9.35 mol;

The same amount of ammonia can be obtained.

The decomposition of ammonium nitrate will release the same amount of ammonia.

Let’s calculate the volume of ammonia.

For this purpose, we multiply the amount of substance by the standard volume of 1 mole of gas (filling 22.40 liters):

V NH3 = 9.35x 22.4 = 209.35 liters;