Under the weight of a load of 3 kg, the spring was compressed by 4 mm. how much mm will it shrink under the weight of 12 kg?
Task data: m1 (initial weight) = 3 kg; Δx1 (initial compression of the spring) = 4 mm; m2 (mass of the second load) = 12 kg.
The compression of the taken spring under the action of a load of 12 kg is determined using the equality: F1 / Δх1 = m1 * g / Δх1 = k = F2 / Δх2 = m2 * g / Δх2, whence Δх2 = m2 * g * Δх1 / (m1 * g) = m2 * Δх1 / m1.
Let’s calculate: Δх2 = 12 * 4/3 = 16 mm.
Answer: Under the weight of a load of 12 kg, the taken spring will be compressed by 16 mm.
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