Under what voltage is 100 m of aluminum wire with a cross section of 0.5 mm ^ 2 switched on

Under what voltage is 100 m of aluminum wire with a cross section of 0.5 mm ^ 2 switched on, if the current in the circuit is 2 A?

l = 100 m. S = 0.5 mm ^ 2 = 0.5 * 10 ^ -6 m ^ 2. I = 2 A. ρ = 2.8 * 10 ^ -8 Ohm * m.
U -?
Let’s write Ohm’s law: I = U / R. R = ρ * l / S. I = U * S / ρ * l. U = I * ρ * l / S. U = 2 A * 2.8 * 10 ^ -8 Ohm * m * 100 m / 0.5 * 10 ^ -6 m ^ 2 = 1120 * 10 ^ -2 B = 11.2 V.
Answer: the wire is switched on under voltage U = 11.2 V.