Upon complete combustion of 3 mol of unbranched alkane, 201.6 liters of carbon dioxide were released.

Upon complete combustion of 3 mol of unbranched alkane, 201.6 liters of carbon dioxide were released. What is the alkane formula. Write the equation for the corresponding reaction.

1. Let’s compose the general equation of alkane combustion:

CnH2n + 2 + O2 → nCO2 + (n + 1) H2O;

2.Calculate the chemical amount of released carbon dioxide:

n (CO2) = V (CO2): Vm = 201.6: 22.4 = 9 mol;

3.Let’s find the index n in the alkane formula from the proportion compiled according to the combustion reaction equation:

1 mole of alkane gives n mole of carbon dioxide;

3 mol alkane – 9 mol CO2;

n = 9 * 1: 3 = 3;

4.The alkane formula is C3H8, we write the equation:

С3H8 + O2 → 3CO2 + 4H2O.

Answer: C3H8 propane.