Upon interaction of 12 g of magnesium with an excess of hydrochloric acid

Upon interaction of 12 g of magnesium with an excess of hydrochloric acid, 10 liters of hydrogen are released. Calculate the volume fraction of the reaction product yield.

Magnesium interacts with hydrochloric acid. In this case, magnesium chloride is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + 2HCl = MgCl2 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 12/24 = 0.5 mol;

The same amount of hydrogen will be synthesized.

Let’s calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 0.5 x 22.4 = 11.2 liters;

The volume fraction of the reaction product yield is:

K = 10 / 11.2 = 0.893 = 89.3%;