Upon interaction of 30 g of sulfuric acid with zinc, gas was released. Determine the mass and volume of the gas.

Let’s implement the solution:
1. Let’s compose the equation according to the problem statement:
m = 30 g. X g. -? X l. -?
H2SO4 + Zn = ZnSO4 + H2 – OBP, hydrogen is evolved;
2. Calculation:
M (H2SO4) = 98 g / mol;
M (H2) = 2 g / mol;
3. Determine the amount of substances:
Y (H2SO4) = m / M = 30/98 = 0.306 mol;
Y (H2) = 0.306 mol since the amount of these substances according to the equation is 1 mol.
3. Find the volume, mass of the product:
V (H2) = 0.306 * 22.4 = 6.85 L;
m (H2) = Y * M = 0.306 * 2 = 0.612 l.
Answer: hydrogen was obtained with a mass of 6.85 g, a volume of 0.612 liters.