Upon oxidation of 12 grams of propanol, 10 g of the corresponding aldehyde was obtained.

Upon oxidation of 12 grams of propanol, 10 g of the corresponding aldehyde was obtained. Calculate the yield of the reaction product from the theoretically possible?

Let’s find the amount of substance С3Н7ОН.

n = m: M.

M (C3H7OH) = 60 g / mol.

n = 12 g: 60 g / mol = 0.2 mol.

Let’s compose the reaction equation. Let’s find the quantitative ratios of substances.

С3Н7ОН + [O] → СН3CH2СОН + Н2О.

According to the reaction equation, 1 mol of С3Н7ОН is 1 mol of СН3СН2СОН. The substances are in quantitative ratios of 1: 1.

n (CH3CH2COH) = n (C3H7OH) = 0.2 mol.

Let’s find the mass of CH3CH2SON.

M (CH3CH2COH) = 58 g / mol.

m = n × M.

m = 58 g / mol × 0.2 mol = 11.6 g (theory).

11.6 g – 100%

10 g – x%,

X = (10 × 100%): 11.6 = 86.21%.

Answer: 86.21%.