Upon the interaction of 2 mol of sulfuric acid with lead nitrate, a precipitate was formed. Find its mass.
| September 22, 2021 | education
Given:
n (H2SO4) = 2 mol
Find: m (PbSO4)
Solution:
1) H2SO4 + Pb (NO3) 2 -> PbSO4 + HNO3
2) according to the equation n (H2SO4) = n (PbSO4) = 2 mol
3) m (PbSO4) = 2 * 303 = 606 g
Answer: 606.
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