Using a lever, the builder lifts a concrete block weighing 150 kg. What is the smaller lever arm

Using a lever, the builder lifts a concrete block weighing 150 kg. What is the smaller lever arm if a force of 500 N is applied to the larger lever arm equal to 2 m.

Initial data: m (concrete block weight) = 150 kg; l1 (length of the larger lever arm) = 2 m; F1 (force applied to the larger arm) = 500 N.

Reference data: g (acceleration due to gravity) = 9.8 m / s ^ 2.

Let us express the length of the smaller arm of the lever from the following ratio (the rule of equilibrium of the lever): F1 / F2 = l1 / l2.

l2 = F1 * l1 / F2 = F1 * l1 / Fт = F1 * l1 / mg.

Let’s do the calculation:

l2 = 500 * 2 / (150 * 9.8) = 0.68 m.

Answer: The length of the smaller arm is 0.68 m.