Using a movable block, the efficiency of which is 91%, the load is evenly lifted, acting on the rope with

Using a movable block, the efficiency of which is 91%, the load is evenly lifted, acting on the rope with a force of 220 N. Determine the weight of the load.

Given: η (efficiency of the used mobile unit) = 91% (0.91); uniform movement of the load; F (force acting on the rope) = 220 N.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To find the mass of the lifted load, we apply the formula: η = Ap / Az = m * g * h / (F * S) = m * g * h / (F * 2h) = m * g / (F * 2), whence m = F * 2 * η / g.

Let’s calculate: m = 220 * 2 * 0.91 / 10 = 40.04 kg.

Answer: The weight of the cargo is 40.04 kg.