Using a screw jack, lift a load weighing 2 tons. Determine the force applied to the end of the jack

Using a screw jack, lift a load weighing 2 tons. Determine the force applied to the end of the jack handle if, when lifting the load by 1 mm, the end of the jack moves by 25 cm.

Data: m (cargo mass) = 2 t (in SI m = 2 * 10 ^ 3 kg); h (lift height) = 1 mm (in SI h = 1 * 10 ^ -3 m); S (movement of the end of the handle) = 25 cm (in SI S = 25 * 10 ^ -2 m).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the force that is required to be applied to the jack handle, we apply the equality: Ap = Az, where Ap = ΔEp = m * g * h and Az = F * S; F = m * g * h / S.

Calculation: F = 2 * 10 ^ 3 * 10 * 1 * 10 ^ -3 / (25 * 10 ^ -2) = 80 N.

Answer: A force of 80 N must be applied to the jack handle.