Using the electronic balance method, create the reaction equation: 2NH3 = N2 + 3H2 Determine the oxidizing agent and the reducing agent.
2N (-3) H (+3) = N₂ (0) + 3H₂ (0)
N₂ (0) + 6e⁻ = 2N (-3) I 6 1 I oxidizing agent, reduction.
H₂ (0) – 2e⁻ = 2H (⁺) I 2 3 I reducing agent, oxidation.
The common denominator is 6, so we divide 6 by 6, the oxidizer has a coefficient of 1, and 6 we divide by 2 will be 3, which means we put 3 on the reducing agent.
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