Using the electronic balance method, write the reaction equation: P + HNO3 + H2O → H3PO4 + NO ↑

Phosphorus reacts with nitric acid, which is a strong oxidizing agent. Determine the oxidation state of the reactants. Let’s compose electronic equations:
P- 5e = P5 + | 3 – reducing agent;
N5 + + 3e = N2 + | 5 – oxidizing agent.
We compose the molecular equation:
3P + 5HNO3 + 2H2O = 3H3PO4 + 5NO;
Oxygen test: 17 = 17
In this reaction, phosphorus reacts with concentrated nitric acid, which is a strong oxidizing agent. Phosphorus is oxidized to phosphoric acid, nitric acid is reduced to nitric oxide.

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