# Using the equation of combustion of acetylene 2C2H2 + 5O2 = 4CO2 + 2H2O, calculate how much

Using the equation of combustion of acetylene 2C2H2 + 5O2 = 4CO2 + 2H2O, calculate how much acetylene has completely burned out if the volume of the resulting carbon dioxide was 20 liters?

Let’s implement the solution:
1. In accordance with the condition of the problem, write the data:
X l. -? V = 20 l;
2С2Н2 + 5О2 = 4СО2 + 2Н2О + Q – combustion is accompanied by the release of carbon monoxide (4) and water;
2. Proportions:
1 mol of gas at normal level – 22.4 liters;
X mol (CO2) – 20 liters. hence, X mol (CO2) = 1 * 20 / 22.4 = 0.89 mol;
X mol (C2H2) – 0.89 mol (CO2);
-2 mol – 4 mol from here, X mol (C2H2) = 2 * 0.89 / 4 = 0.445 mol.
3. Find the volume of C2H2:
V (C2H2) = 0.445 * 22.4 = 9.97 l.
Answer: to carry out the process, acetylene with a volume of 9.97 liters is required.

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