Using the reaction equation KOH + HNO3 = KNO3 + H2O, calculate the mass of salt obtained

Using the reaction equation KOH + HNO3 = KNO3 + H2O, calculate the mass of salt obtained if 5.6 g of potassium hydroxide entered the reaction.

Let’s implement the solution:
1. According to the condition of the problem, we write the data:
KOH + HNO3 = KNO3 + H2O – ion exchange, obtained potassium nitrate;
2. Calculations:
M (KOH) = 56.1 g / mol;
M (KNO3) = 101.1 g / mol.
3. Determine the amount of the original substance:
Y (KOH) = m / M = 5.6 / 56.1 = 0.09 mol;
Y (KNO3) = 0.09 mol.
4. Find the mass of the product:
m (KNO3) = Y / M = 0.09 * 101.1 = 9.09 g.
Answer: received potassium nitrate weighing 9.09 g.