Using the reaction equation Zn (OH) 2 = ZnO + H20, determine the mass of zinc oxide, which is formed

Using the reaction equation Zn (OH) 2 = ZnO + H20, determine the mass of zinc oxide, which is formed during the decomposition of 19.8 g of the starting material.

Let’s execute the solution:
1. We make the equation:
m = 19.8 g. X g. -?
Zn (OH) 2 = ZnO + H2O – decomposition, zinc oxide, water is released;
2. We establish the molar masses of substances:
MZn (OH) 2 = 99.3 g / mol;
M (ZnO) = 81.3 g / mol.
3. Determine the amount of the original substance:
Y Zn (OH) 2 = m / M = 19.8 / 99.3 = 0.199 mol;
Y (ZnO) = 0.199 mol since the amount of substances is 1 mol each, which confirms the equation.
4. Product weight:
m (ZnO) = Y * M = 0.199 * 81.3 = 16.18 g.
Answer: zinc oxide was obtained with a mass of 16.18 g.



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