Using the reaction equation Zn (OH) 2 = ZnO + H2O Find the mass of zinc oxide formed during

| June 16, 2021 | education

Using the reaction equation Zn (OH) 2 = ZnO + H2O Find the mass of zinc oxide formed during the decomposition of 19.8 g of the starting material.

Find the amount of zinc hydroxide substance Zn (OH) 2 by the formula:

n = m: M.

M (Zn (OH) 2) = 65 + 2 × 17 = 99 g / mol.

n = 19.8 g: 99 g / mol = 0.2 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Zn (OH) 2 = ZnO + H2O.

According to the reaction equation, 1 mol of zinc hydroxide accounts for 1 mol of zinc oxide. Substances are in quantitative ratios 1: 1.

The amount of zinc oxide and zinc hydroxide substance will be equal.

n (ZnO) = n (Zn (OH) 2) = 0.2 mol.

Find the mass of zinc oxide.

m = n × M,

M (ZnO) = 65 + 16 = 81 g / mol.

m = 0.2 mol × 81 g / mol = 16.2 g.

Answer: 16.2 g.



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