Vapor density of aldehyde with respect to methane = 2.75. What is the name of this aldehyde.

Let’s write down the solution according to the condition of the problem:
1. Given: R – COH – organic matter refers to aldehydes.
D (CH4) = 2.75;
M (CH4) = 16 g / mol;
Define: SHNUOZ.
2. Let’s calculate the molar mass:
M (CxHyOz) = M (CH4) * D (CH4) = 16 * 2.75 = 44 g / mol.
3. Establish the formula:
CnH2n + 1COH is the general formula for aldehydes.
12n + 2 + 1 + 12 + 16 + 1 = 44;
12n = 44-32;
12n = 12;
n = 1;
CH2O is the simplest formula;
C2H4O – ethanal;
Checking: M (C2H4O) = 44 g / mol.
Answer: C2H4O – acetaldehyde.



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