Vehicle fuel tank capacity V = 50 liters. The weight of gasoline consumed on the path S1 = 100 km

Vehicle fuel tank capacity V = 50 liters. The weight of gasoline consumed on the path S1 = 100 km is P1 = 50H. The density of gasoline is 710 kg / cubic meter. Determine the maximum distance that the car can travel after one refueling. The coefficient g is assumed to be 10 H / kg.

Since the capacity of the car’s fuel tank is V = 50 l = 50 dm ^ 3 = 0.05 m ^ 3, and the density of gasoline is ρ = 710 kg / m ^ 3, then the mass of gasoline m in the tank is found by the formula:

m = ρ ∙ V.

Then the weight of gasoline in the tank will be:

Р = m ∙ g or Р = ρ ∙ V ∙ g, where coefficient g ≈ 10 H / kg.

From the condition of the problem it is known that the weight of gasoline consumed on the way S₁ = 100 km = 100000 m is P₁ = 50 H. Then the maximum path that a car can travel after one refueling is determined from the proportion:

S: S₁ = P: P₁ or S = (P: P₁) ∙ S₁.

We get:

S = (ρ ∙ V ∙ g ∙ S₁): P₁.

Substitute the values ​​of physical quantities in the calculation formula:

S = (710 kg / m ^ 3 ∙ 0.05 m ^ 3 ∙ 10 H / kg ∙ 100000 m): 50 H;

S = 710000 m;

S = 710 km.

Answer: the maximum distance that a car can travel after one refueling is 710 km.