# Vehicle movement is given by the equation x = 15t-150. determine the distance

May 27, 2021 | education

| **Vehicle movement is given by the equation x = 15t-150. determine the distance of the car from the starting point of movement to the coordinate in which it will be in 15 seconds.**

The distance traveled by the car is equal to the difference between the starting and ending points of the car’s location.

x = xk – xn.

The starting point of the vehicle.

Equation of motion: xн = 15t – 150.

Travel time: t = 0.

xо = 15t – 150 = 15 * 0 – 150 = -150.

The end point of the vehicle.

Equation of motion: xk = 15t – 150.

Movement time: t = 15.

xk = 15t – 150 = 15 * 15 – 150 = 75.

Then:

x = xк – xн = 75 – (-150) = 75 + 150 = 225 m.

Answer: The distance traveled by the car is 225 m.

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