Water, alcohol, kerosene and oil were given the same amount of heat. Which of the liquids will heat up the most degrees?

Water, alcohol, kerosene and oil were given the same amount of heat. Which of the liquids will heat up the most degrees? The masses of all liquids are the same. 1) Oil 2) kerosene 3) water 4) alcohol

Let’s consider each case separately.
Let water, alcohol, kerosene and oil be given 135000J (135kJ) of heat and their masses are equal to 25kg. According to the formula Q = cm (t2-t1), we also need the heat capacity of each of these substances, which we take from the table of heat capacities (Water = 4200J, Alcohol = 2500J, Kerosene = 2100J, Oil = 1700J)
To find the temperature (t2-t1) = Q / c * m
Let’s calculate for each substance:
1) Water (t2-t1) = 135000/25 * 4200 = 1.28
2) Alcohol (t2-t1) = 135000/25 * 2500 = 2.16
3) Kerosene (t2-t1) = 135000/25 * 2100 = 2.57
4) Oil (t2-t1) = 135000/25 * 1700 = 3.17
From the above calculations, it follows that the Oil will heat up by a greater number of degrees.
Answer: 1 (Oil)



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