Water and kerosene were poured into the vessel, the thickness of the lower layer is 1.5 cm and the upper layer is 12 cm

Water and kerosene were poured into the vessel, the thickness of the lower layer is 1.5 cm and the upper layer is 12 cm, to determine the pressure on the bottom of the vessel

Since the density of kerosene ρк = 800 kg / m3 is less than the density of water (ρw = 1000 kg / m3), the kerosene layer is at the top, and the water layer is at the bottom. This means that the height of the water layer is hw = 1.5 cm = 0.015 m, and the kerosene layer is: hc = 12 cm = 0.12 m.

The pressure at the bottom of the vessel is equal to the sum of the pressures from the water layer and the kerosene layer:

p = ρв g hв + ρк g hв,

where g is the acceleration due to gravity, g = 9.8 m / s2.

Thus,

p = 1000 × 9.8 × 0.015 + 800 × 9.8 × 0.12 = 1088 Pa.

Answer: p = 1088 Pa.