Water at room temperature is in a closed vessel. When the vessel is heated to a temperature of 120 degrees

| February 4, 2021 | education

Water at room temperature is in a closed vessel. When the vessel is heated to a temperature of 120 degrees, all the water evaporates, the pressure turns out to be p = 1.6 * 10`6 Pa. What part of the vessel volume was occupied by water at the beginning?

Data: T (considered temperature in the vessel) = 120 ºС = 393 K; P (reached pressure) = 1.6 * 10 ^ 6 Pa.

Constants: R (universal gas constant) = 8.314 J / (K * mol); MH2O (molar mass) = 1.8 * 10 ^ -2 kg / mol; ρw (water density) = 1000 kg / m3.

1) The density of water vapor: P * V = m / MH2O * R * T and ρ = P * MH2O / (R * T) = 1.6 * 10 ^ 6 * 1.8 * 10 ^ -2 / (8.314 * 393) = 8.814 kg / m3.

2) Part of the volume of the vessel with water: k = Vw / Vp = (m / ρw) / (m / ρ) = ρ / ρw = 8.814 / 1000 = 1/113.

Answer: Water occupied 1/113 of the vessel.



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